households with Internet access (a)Find the probability that a randomly selected
ID: 3022178 • Letter: H
Question
households with Internet access
(a)Find the probability that a randomly selected households access the internet in 2010-2011.
(b) What is the probability that a randomly selected households access the Internet at least monthly orat least yearly?
(c)What is the probability that a randomly selected households access the internet at least on monthly basis in 2007-2008?
2006-07 2007-2008 2008-09 2010-2011 2012-13 Every day 3321 3708 4281 5157 5933 At least weekly 1561 1540 1382 1339 1202 At least monthly 185 176 132 148 129 At least yearly 21 26 25 20 23 Never 31 25 33 39 31 Donnot know 19 20 26 21 26 total 5138 5492 5878 6724 7343Explanation / Answer
(a)Find the probability that a randomly selected households access the internet in 2010-2011.
= (5157 + 1339 + 148 + 20) / 6724
= 6664 / 6724
= 0.9910
(b) What is the probability that a randomly selected households access the Internet at least monthly orat least yearly?
=
(c)What is the probability that a randomly selected households access the internet at least on monthly basis in 2007-2008?
= 176 / 5492
= 0.0320
= 3.20%
Hope this helps.
At least monthly 185 176 132 148 129 At least yearly 21 26 25 20 23 Sum 206 202 157 168 152 total 5138 5492 5878 6724 7343 Probability 4.009% 3.678% 2.671% 2.499% 2.070%Related Questions
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