Let\'s suppose we run a company that manufactures baby food. It is essential tha
ID: 3022953 • Letter: L
Question
Let's suppose we run a company that manufactures baby food. It is essential that the preparation have 100 calories per serving. We sample 225 batches and test the calorie content. Our sample statistics are x=96 and s=30.
We need to test H0: =100 against the alternative HA: <100.
If we use a significance level of 0.05, the following picture shows you the rejection region and critical values for the test.
The picture shows a t-distribution with the area to the left of the number -1.652 shaded (total shaded area equals 0.05).
For Blank 1, calculate the test statistic, using the formula
T=x¯s/N
and two decimal places.
Type "yes" in Blank 2 if we should reject H0; type "no" in Blank 2 if we should fail to reject H0.
Find the p-value for this statistic using a t-distribution with 224 degrees of freedom.
Calculate the p-value of the test statistic using Graph>Probability Distribution> and choose the t-distribution with 224 degrees of freedom. Click on the radio button that says "X" and type in your response to Answer 1 (Answer 1 is your "X" value here). Put the p-value into Blank 3 (five decimal places).
Would we reject at the 1% significance level? Type "yes" for reject and "no" for fail to reject in Blank 4.
Explanation / Answer
Formulating the null and alternative hypotheses,
Ho: u >= 100
Ha: u < 100
As we can see, this is a left tailed test.
Thus, getting the critical t,
df = n - 1 = 224
tcrit = - 1.65168456
Getting the test statistic, as
X = sample mean = 96
uo = hypothesized mean = 100
n = sample size = 225
s = standard deviation = 30
Thus, t = (X - uo) * sqrt(n) / s = -2 [ANSWER, TEST STATISTIC]
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Comparing t and tcrit (or, p and significance level), we REJECT THE NULL HYPOTHESIS. [ANSWER: YES]
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Also, the p value is
p = 0.02335 [ANSWER]
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Would we reject at the 1% significance level? Type "yes" for reject and "no" for fail to reject in Blank 4.
As P > 0.01, we dail to reject Ho. [ANSWER: NO]
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