I need help with problems 8-14 s ove the degree mesoure of i he degroe measure a
ID: 3026638 • Letter: I
Question
I need help with problems 8-14
Explanation / Answer
8. theta=arctan(-sqrt3) = arctan(tan(-pi/3)) =-pi/3 =-60 degree
9 .theta=arcsin(sqrt3/2) =arcsin(sin (pi/3))=pi/3 =60 degree
10. theta=cos-14
Does not exist since cos theta lies in [-1,1]
12.sin-1(-0.4153) =-24.54 degree
13. theta=arcsin(-0.6738)=-42.3610 degree
14.y=arccos(0.788)=38.011 degree
.
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