An airplane has an airspeed of 590 klometers per hour bearing N45 E. The wind ve

Question

An airplane has an airspeed of 590 klometers per hour bearing N45 E. The wind velocity is 80 klometers per hour in the direction N30°W. Find the resultant vector representing the path of the plane relative to the ground. What is the ground speed of the plane? What is its direction? What is the actual ground speed of the aircraft? kilometers per hour (Round to the nearest tenth as needed.) What is the actual direction of the aircraft relative to due north? nteneast of noth nten Round to the nearest tenth as needed.) ok edia 0

Explanation / Answer

airline componnet = 590 cos 45 , 590 sin 45

= 417.193 , 417.193

wind componnet = 80 cos 120 , 80 sin 120

= -40 , 69.282

|airline + wind | = < 377.193 , 486.475 >

ground speed = sqrt ( 377.193^2 + 486.475^2 ) = 615.6 km / h

direction = tan^-1 ( 486.475 / 377.193 ) = 52.21145

due north = 90 - 52.21145 = 37.8 degrees east of north

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