The probability of two or more nonconforming in a sample is equal to p(0) + p(1)

Question

The probability of two or more nonconforming in a sample is equal to p(0) + p(1) p(0) times p(1) times p(2) p(0) times p(1) p(0) times p(1) p(0) + p(1) + p(2) None of the above Which is not true about binomial distribution? Probability of success remains constant from one trial to next Trials must be independent of each other Probability of each trial must be between 0 and 1 Trial can have only one out of the two possible outcomes Standard deviation is equal to the squareroot of the mean If p is the probability of success, and n is the sample size of a binomial distribution, which of the following it true? The distribution becomes symmetrical as p-derivates from 0.5 Smaller the value of p, more symmetrical the distribution becomes As n becomes smaller, the more symmetrical distribution becomes For a Riven value of p, as n increases, the distribution becomes more symmetrical None of the above A company that makes cartons finds that the probability of producing a carton with a puncture is 0.05, probability that a carton has a smashed comer is 0.08, probability that a carton has a puncture and smashed corner is 0.004. Events of "selecting a carton with a puncture" and "selecting" a carton with a smashed corner are Independent Dependent Not mutually exclusive Mutually exclusive Exhaustive Based on the information given in question 9 above, if the inspector selects a carton at random, the probability that the carton has a puncture or has a smashed corner would be about 0.08 0.05 0.004 0.126 0.136 The probability that a salesperson makes a sale on a call is 0.80. Assuming independent events the probability that two calls made in a day will produce both sales is 0.08 0.16 0.20 0.64 None of the above

Explanation / Answer

6. a

7. d

8. b

9. c

10. d, (0.08+0.05-0.004=0.126)

11 d, (0.8*0.8=0.64)

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