A 9 times 9 matrix has only two eigenvalues. lambda_1 = 3 and lambda_2 = 2, wher

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A 9 times 9 matrix has only two eigenvalues. lambda_1 = 3 and lambda_2 = 2, where lambda_1 repeats once (algebraic multiplicity = 2) and lambda_2 repeats 6 times (algebraic multiplicity = 7). From lambda_1 = 3. one eigenvector and one generalized eigenvector are found. From lambda_2 = 1. only three linearly independent eigenvectors, 0_3, 0_4, and 0_5 are found. Find and write the Jordan canonical matrix for cases below. You are required to enter the value of every element of the 9 times 9 matrix, clearly. Please do not enter values and locations ambiguously and then argue with me. a. 0_3 breeds 4 linearly independent generalized eigenvectors. b. 0_3 breeds 2 linearly independent generalized eigenvectors and 0_4 breeds 2. c. 0_3 breeds 1 linearly independent generalized eigenvectors and 0_4 breeds 3. d. 0_3 breeds 2 linearly independent generalized eigenvectors, 0_4 breeds 1, and 0_5 breeds 1.

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