solve when x is 10.5m and show dimension analysis. U = -wx^2/24ei (x^2 + 6l^2 -

Question

solve when x is 10.5m and show dimension analysis. U = -wx^2/24ei (x^2 + 6l^2 - 4lx). Here u in the de fleet ion (up I m defined to be positive), w in the uniformly distributed load (force per unit length) (down is defined to be positive), x is the distance from the wall, E is Young's for the beam material. I is the second- moment of area for beam shape and L is the beam's total length. For this problem, the values of the parameters are. w = 3 k N/m E = 200 GP a I = 986.0 times 10^6 mm^4 L = 10.5 m

Explanation / Answer

v = wx^2 / 24 EI ( x^2 + 6L^2 - 4Lx )

w = 3kN / m

E = 200 GPa

I = 986 x 10^6 mm^4

L = 10.5 m

x = 10.5 m

plugging the values in the formula

v = 3*(10.5)^2 / 24 (200)(986 x 10^6) ( (10.5)^2 + 6(10.5)^2 - 4(10.5)(10.5) )

v = 6.98 x 10^-11 ( 330.75 ) = 2.308 x 10^-8

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