If the discriminant, b^- 4ac, is equal to zero, the graph of the quadratic funct

Question

If the discriminant, b^- 4ac, is equal to zero, the graph of the quadratic function f(x) = ax^2 + bx + c has no x-intercepts. A power function of degree n is a function of the form f(x) = ax^n, where n is an integer. End behavior, the graph of the function f(x) = 3x^4 - 6x^2 + 2x + 5 resembles y = x^4 for large values of |x| If the degree of the numerator in a rational function equals the degree of the denominator, then the ratio of the leading coefficients gives rise to the horizontal asymptote. The graph of a rational function never interjects a horizontal asymptote. The inequality x^2 + x + 4 > 0 is true for all x. If f is a polynomial function of degree 4 and if f(z) = 5, then f(x)/x - 2 = p(x) + 5/x - 2 A polynomial function of degree 4 with real coefficients could have -3, 2 + i, 2 - i, and -3 + 5i as its zeros. Use the quadratic function y = x^2 - 12x + 35. Explain whether is has a maximum or minimum point. Find the coordinates of this point. Find the zeros of the quadratic function.

Explanation / Answer

5.

(a)

y = Ax^2 + Bx + C

given equation

y = x^2 - 12x + 35

if in a quadratic equation,

A > 0

and B^2 - 4AC > 0

then equation will have minimum

A = 1 > 0

12^2 - 4*35*1 = 4 > 0

this equation will have minimum.

(b)

x^2 - 12x + 35 = x^2 - 12x + 36 - 1

= (x - 6)^2 - 1

SO this equation will have minima at

x = 6

and minimum value of quadratic will be = 1

Cooradinates = (6, 1)

(c)

x^2 -12x + 35 = 0

x = [-(-12) +/- sqrt (12^2 - 35*4*1)]/2

x = [12 +/- 2]/2

x = 7 or x = 5

OR

x^2 - 7x - 5x + 35 = 0

x(x - 7) - 5(x - 7) = 0

(x-5)(x - 7) = 0

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