In 2004, a school\'s population was 1058. By 2008 the population had grown to 18
ID: 3032280 • Letter: I
Question
In 2004, a school's population was 1058. By 2008 the population had grown to 1802. Assume the population is changing linearly. How much did the population grow between the year 2004 and 2008? students How long did it take for the population to grow from 1058 students to 1802? years What is the average population growth per year? students per year What was the population in the year 2000? students Find an equation for the population, P, of the school t years after 2000. Using your equation, predict the population of the school in 2011. Students.Explanation / Answer
a. The school's population had grown by (1802-1058)= 744 students between 2004 and 2008.
b. It took 4 years (2008-2004) for the population to grow from 1058 students to 1802 students.
c. The average population growth per year is 744/4 = 186 students per year.
d. Assuming the population growth to be uniform, the growth of student population between the years 2000 and 2004 should also be 744. Then, the school's population in the year 2000 = 1058-744 = 318.
e. The average population growth of the school is 186 students per year. Hence in t years after the year 2000, the population growth of the school will be 186 t students. Then the equation for the population, P(t) of the school t years after 2000 is P(t) = 318+186 t.
f. For the year 2011, t = 2011-2000 = 11. Hence the population of the school in 2011 ( i.e. 11 years after the year 2000) will be 318+11*186 = 318 + 2046 = 2364 students.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.