ork4 math utah.edu/webwork2/math1010fall20 16-19/05 Apps MaxMin/3/?userac-aib&ef

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ork4 math utah.edu/webwork2/math1010fall20 16-19/05 Apps MaxMin/3/?userac-aib&effectiveuserac-aib;& d x U Holiday Sale 2016 Ulta Bea WedwoA: or K MATHEMATICAL ASS0CIATION 0F AMERICA ebwork math1010fall2016-19 05d apps maxmin 3 d Apps Max Min: Problem 3 Prev p Next pts) A rectangle has an area of 209 cm2 and a perimeter of 60 cm. What are its dimensions? Its length is Its width is ote: You can earn partial credit on this problem. Preview Answers Submit Answers ou have attempted this problem 0 times. ou have unlimited attempts remaining. Page ed at 11/22/2016 at 10:58am MST WeBWork 1996-201 MacBook Air

Explanation / Answer

Dear Student Thank you for using Chegg !! Given Area = 209 cm^2 Perimeter = 60 cm Solution Let length of rectangle be l and breadth be b Therefore lXb = 209 2(l+b) = 60 l+b = 30 b = 30-l (1) l(30-l) = 209 l^2 - 30l + 209 =0 (l-19)(l-11)=0 l = 11,19 cm b = 19,11 Since length > breadth => length = 19 cm Breadth = 11 cm

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