Consider a line passing through (-2, 1) and (3, -2). Find the slope of the line.

Question

Consider a line passing through (-2, 1) and (3, -2). Find the slope of the line. Find the equation of the line. Write your answer in slope-intercept form. Find the equation of the line parallel to it and passing through (0, -2). Consider the y-axis in the graph. Find the slope of the line. Find the equation of the line. Consider the linear equation - 2x + 3y = 6. Fin d the slope and the y-intercept of the line. Find the slope of a line perpendicular to -2x + 3y = 6. Find the equation of the line perpendicular to -2x + 3y = 6 and passing through (1, -3).

Explanation / Answer

(-2, 1) and ( 3, -2)

a) slope = ( -2 -1)/( 3+2) = -3/5

b) slope intercept form of line : y = mx + c where m is slope and c is y intercept

y = -3x/5 + c .Now find c using any 1 point

1 = -3*-2/5 + c ; c = 1 - 6/5 = -1/5

y = -3x/5 - 1/5

c) Line parallel and passing through ( 0 , -2)

paralle line would have same slope:

y = -3x/5 + c .Find using point ( 0, -2)

So, y = -3x/5 -2

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