Take a Test-Aminata Kargbo Internet Explorer https//www MAT 01024 xD01Intrm. Alg
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Take a Test-Aminata Kargbo Internet Explorer https//www MAT 01024 xD01Intrm. Alg 2017SP 58 17 543 PM Quiz Me: Quiz Me: 13.17-3-2 Interpret graphs of functions. This Question: 1 pt 3 of 5 This Quiz: 5 pts possible A ingrad manufacturer developed a model for the prot expected when a given number of suhing rods is produced the graph of the Profit tundion is shown Usete graph answer pati (ajthrough gl below. the manufacturer produces 5000 fahing rods per year, what the expected profn The expected prof S30000 b For what intervals of fishing rods produced wil the expected increase? 3000015000 comena separate answers as needed Type your answer in inomval notason using an open interviks) Use comma to separate the endpoints of interval, but do use oammas example wite the number 10 000 10000) c For what interval( of fishing nodi produced wa the expected profit decrease? separate the endpoints of the in a year? d. What the maximum profit that can be expected to select your arawerp)Explanation / Answer
Answer a: $90000 (As explained below)
Each major unit on the Y axis is equivalent to $30000. So, the value corresponding to X-value of 5000 is $60000 + $30000 = $90000.
Answer b: (0,3000) and (5000, 8000) (As explained below)
The curve reverses trajectory and points in the downward direction at two points corresponding the X-axis, one at the 3000 and another at 8000. Before that it is rising from the start i.e.0 and 5000, respectively. So, the intervals that correspond to increased profit are (0,3000) and (5000,8000).
Answer c: (3000,5000) and (8000, 12000) (As explained below)
The curve reverses trajectory and points in the downward direction at two points corresponding the X-axis, one at the 3000 and another at 8000. After that it continues its downward journey upto the points 5000 and 12000, respectively. So, the intervals that correspond to decreased profit are (3000,5000) and (8000,12000).
Answer d: $240000 (As explained below)
The peak of the curve indicates the maximum profit expected. And that is achieved at y-axis corresponding to $240000.
Answer e: $30 (As explained below)
At maximum profit of $240000 the corresponding X-value is 8000. So, per unit profit = $240000 / 8000 = $30
Answer f: $50 (As explained below)
For 3000 units, Y-value corresponding is $15000. So, per unit profit = $15000 / 3000 = $50.
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