How would I explain this with words in steps? 2 lambda ^7 - 128 lambda mu ^6 = 2

Question

How would I explain this with words in steps? 2 lambda ^7 - 128 lambda mu ^6 = 2 lambda ^7 - 2 times 64 lambda mu ^6 = 2 lambda lambda ^7 - 2 times 64 lambda mu ^6 = 2 lambda (lambda ^6 - 64 mu ^6) = 2 lambda (lambda ^6 - 2^6 mu ^6) = 2 (lambda ^6 - (2 mu)^6) = 2 lambda ((lambda ^2)^3) - ((2 mu)^2)^3) For4mula: a^3 - b^3 = (a - b) (a^2 + ab b^2) = 2 lambda (lambda ^2 - (2 mu)^2) ((lambda ^2)^2 + lambda ^2. (2 mu)^2 + ((2 mu)^2)^2) = 2 lambda (lambda - 2 lambda) (lambda ^4 + 4 lambda ^2 mu ^2 + 16 mu ^4) Formula: a^2 - b^2 = (a - b) (a + b)

Explanation / Answer

in the first step taking 2lamda common from both the parts

64 is written as 2^6

converting it into a^3 - b^3 form for using the given identity

then converting it into a^2 - b^2 form for using the given identity

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.