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A cognitive retraining clinic assists outpatient victims of head injury, anoxia,

ID: 3040189 • Letter: A

Question

A cognitive retraining clinic assists outpatient victims of head injury, anoxia, or other conditions that result in cognitive impairment. Each incoming patient is evaluated to establish an appropriate treatment program and estimated length of stay. To see if the evaluation teams are consistent, 12 randomly chosen patients are separately evaluated by two expert teams (A and B) as shown. Estimated Length of Stay in Weeks Patient Team 1 9 10 11 12 39 39 35 1 34 23 13 A 20 35 B 42 48 28 47 517222643 48 38 17 47 35 30 (a) Choose the appropriate hypotheses. Assume d is the difference in mean lengths of team A and team B (b) Specify the decision rule at the .10 level of significance.(Round your answers to 3 decimal places. A negative values should be indicated by a minus sign.) Reject the null hypothesis if the p-value is (click to select) 0.10 or if tcalc (c) Find the test statistic tcalc (Round your answer to 3 decimal places. A negative value should be indicated by a minus sign.) tcalc (d) Find the p-value. (Round your answer to 3 decimal places. A negative value should be indicated by a minus sign.) p-value (e) Make a decision. We (Click to select) the null hypothesis. (f) State your conclusion We (Click to select) conclude that the evaluator teams are consistent in their estimates. or tcalc

Explanation / Answer

The statistical software output for this problem is:

Paired T hypothesis test:
D = 1 - 2 : Mean of the difference between Team A and Team B
H0 : D = 0
HA : D 0
Hypothesis test results:

Hence,

a) Hypotheses: Option C is correct.

b) Reject the null hypothesis if p - value is less than 0.10 or if tcalc < -1.796 or tcalc > 1.796

c) tcalc = -1.523

d) P - value = 0.156

e) Do not reject

f) Can not

Difference Mean Std. Err. DF T-Stat P-value Team A - Team B -5.3333333 3.5018033 11 -1.5230248 0.156
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