A medical social worker is interested in examining the relationship between pati
ID: 3040199 • Letter: A
Question
A medical social worker is interested in examining the relationship between patients who receive social support by family members (yes/no) and the patients’ outcome (failure/success). She collected data over a period of a month (N=100). A chi square analysis revealed the following: 2= 5.65, df = ?, p = .01. A medical social worker is interested in examining the relationship between patients who receive social support by family members (yes/no) and the patients’ outcome (failure/success). She collected data over a period of a month (N=100). A chi square analysis revealed the following: 2= 5.65, df = ?, p = .01.Explanation / Answer
Solution:-
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
H0: Social support by family members and the patients outcome are independent.
Ha: Social support by family members and the patients outcome are not independent.
Formulate an analysis plan. For this analysis, the significance level is 0.05. Using sample data, we will conduct a chi-square test for independence.
Analyze sample data. Applying the chi-square test for independence to sample data, we compute the degrees of freedom, the expected frequency counts, and the chi-square test statistic. Based on the chi-square statistic and the degrees of freedom, we determine the P-value.
D.F = (r - 1)(c - 1)
D.F = (2 - 1)(2 - 1)
D.F = 1
2 = [ (Or,c - Er,c)2 / Er,c ]
2 = 5.65
where DF is the degrees of freedom.
The P-value is the probability that a chi-square statistic having 1 degrees of freedom is more extreme than 5.65.
We use the Chi-Square Distribution Calculator to find P(2 > 5.65) = 0.01
Interpret results. Since the P-value (0.01) is less than the significance level (0.05), we cannot accept the null hypothesis. Thus, we conclude that there is a relationship between patients who receive social support by family members (yes/no) and the patients’ outcome (failure/success).
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