(1 point) The editor of a magazine knows that 41 % of all people who subscribe t
ID: 3040249 • Letter: #
Question
(1 point) The editor of a magazine knows that 41 % of all people who subscribe to the magazine do not renew their subscriptions. In an attempt to decrease this percentage, current subscribers are offered a renewal offer - one that offers current subscribers to renew their subscription at a substantially reduced price. After a period of six-months, the magazine editor wishes to investigate if this renewal offer does decrease the percentage of subscribers who do not renew subscriptions, or p. (a) Choose the correct statistical hypotheses. A, Ho : p = 0.41 B. Ho : p = 0.41 C. Ho : p = 0.41 D. Ho : p = 0.41 E. H0 : p = 0.41 F. Ho : p = 0.41 HA :p>0.41 HA : p 0.41 HA: p0.41 HA : pExplanation / Answer
a) option B is correct
b) std error =(p*(1-p)/n)1/2 =0.0348
for 0.05 level critical z =-1.645
here rejection region phat<p +z*std error
phat<0.41-1.645*0.0348
phat<0.3528
therfore sample size n<0.3528*200
n<70.55
hence n=70
c)
as p vlaue is greater than 0.05 level ; we cna not reject null hypothesis which might be a type II errror
option B
d)
Hypothesized proportion =p o = 0.41 true proportion =pa = 0.36 sample size =n = 200 standard error of hypothesized proportion=Po=(po(1-po)/n)= 0.0348 standard error of true proportion=Pa=(pa(1-pa)/n) = 0.0339 for 0.05 level and left tailed test critival value Z = -1.6449 rejection region: p <= po+Z*Po or p <= 0.3528 type II error =probability of not rejecting = P(Z >(0.3528- pa)/Pa)) = P(Z >-0.2121) = 0.5840 power of the test =1- = 0.4160Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.