Suppose there is a group of 8 students. They will be partitioned in to two group

Question

Suppose there is a group of 8 students. They will be partitioned in to two groups of 2 and 6. How many possible ways are there in partitioning them?
What is the probability that 4 dice rolls are needed before getting a number greater than 5?

Suppose there is a group of 8 students. They will be partitioned in to two groups of 2 and 6. How many possible ways are there in partitioning them?
What is the probability that 4 dice rolls are needed before getting a number greater than 5?


What is the probability that 4 dice rolls are needed before getting a number greater than 5?

Explanation / Answer

a) no of ways of partitioning = 8C2 = 28

b) probability = (5/6)^3 * (1/6) = 0.096

                                    

                                         

                                   

                                      

                      

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