A ball is drawn at random from a vase containing one red ball and one black ball

Question

A ball is drawn at random from a vase containing one red ball and one black ball. We conduct an experiment where we draw two balls out as follows (1) For the first draw we do the following: If the black ball is drawn, we put it back into the vase. If the red ball is drawn, we put it back into the vase, but also put in two more red balls. (2) For the second draw we simply remove 1 ball from the vase. What is the probability that we drew a black ball on both the first and second draw? O 1/4 O 1/2 O 3/4 O None of these

Explanation / Answer

P(black ball on both draw) = P(first drawn ball is black) * P(second drawn ball is black)

                                         = 1/2 * 1/2

                                         = 1/4

Option-A) 1/4

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.