A cross is made between fruit flies. Its expected that 1/4 of the progeny will h

Question

A cross is made between fruit flies. Its expected that 1/4 of the progeny will have the trait of blue eyes and 1/2 will have the trait of larger wings. Following mendels rules...

** I think these are all and/or problems, but i would still like to see how you set these up**

A) What is the probability that a fly will have NEITHER of the two traits?

B) What is the probability that a fly will have ATLEAST ONE of the two traits?

C) What is the probability that a fly will have ONLY ONE of the two traits?

D) What is the probability that a fly will have BOTH traits?

E) If 8 flies are taken what is the probabilty that they will all have blue eyes?

Explanation / Answer

a) P( neither of the two traits) = 1 - (1/4 * 1/2) = 0.857

b) P( at least one of the two traits) = 1 - P(neither of the two traits) = 1 - 0.857 = 0.143

c) P(only one of the two traits) = 1/4 * 1/2 + 1/2 * 3/4 = 0.5

d) P( fly will have both traits) = 1/4 * 1/2 = 0.125

e) P(All 8 have blue eyes) = (1/4)^8 = 0.00002

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