Show steps please. This is a problem on blood type. Each parent has 3 alleles, {
ID: 3041699 • Letter: S
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Show steps please. This is a problem on blood type. Each parent has 3 alleles, {a, b, o}. Each parent gives one allele to the offspring, and the combination (known as genotype) determines the blood type of the offspring, {A, B, AB, O}. The ordering of the alleles does not matter, i.e., ab and ba give rise to the same blood type. The following table summarizes the allele pairs and blood types.
(a) What is the probability the child is of type B blood?
(b) Find the probability that at least one of the alleles the child has is a b.
(c) Given that one of the alleles is o, what is the probability that the child has blood type A?
(d) Given that the child has no o alleles, what is the probability that the child does not have blood type AB?
Genotype aa ab ao bb bo oo Blood type A AB A B B OExplanation / Answer
male parent can give either of the three alleles
female parent can give either of the three alleles
Total possibilities = 3 * 3 = 9
a) There are three possibilities when a child have type B blood = {bb, bo, ob}
probability = 3 / 9 = 1 / 3
b)atleast 1 b allele = {bb, bo, ob, ab, ba}
probability = 5 / 9
c) there are 5 possibilities when one of the alleles is o = {oo, oa, ao, ob, bo}
out of these 5, 2 possibilities make blood type A = {oa, ao}
required probability = 2/5
d) there are 4 possibilities when no alleles is o = {aa, bb, ab, ba}
out of them 2 possibilities make AB blood type = {ab, ba}
required probability = 2/4 = 1/2
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