3. The data set below is a summary of the marks (as a percentage) on Test #1 for

Question

3. The data set below is a summary of the marks (as a percentage) on Test #1 for last year's Stats 2B03 class stem-and-leaf of C2 N = 439 Leaf Unit 1.0 1 1 7 25 4 22 52 5 22 85 6 111111111111111666666666666666666 2 3 333388 (105) 8 0000000000000000000000000000000000000000000055555555555555555555555+ 183 9 0000000000000000000000000000000000000000000000000000000000000000055+ 38 10 00000000000000000000000000000000000000 If a student is randomly selected from the above data set, find the probability that they got a mark of at least 80% given that they passed the test (i.e., given that they got at least 50%). (a).8424 (b).4420 (c).6560 (d).6956 (e).7874

Explanation / Answer

From stem 1 to 4 we have 25 data values. So number of students that got at least 50% marks is

439 - 25 = 414

Out of 414 students that got at least 50% marks 105+183 = 288 students (sum of counts of stems 8 and 9) got at least 80% marks so

288 / 414 = 0.6957

Hence, correct option is (d).

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