mally the distribution is norm rs per of 4.5 hours. Ass week W ng TV w sd.us/D t
ID: 3041951 • Letter: M
Question
mally the distribution is norm rs per of 4.5 hours. Ass week W ng TV w sd.us/D t an average of 34 Nutrition/TV.pd women s uth Dakota distributed. The goal is to find the probability a random woman would watch less than 30 hours of TV per week. a) Click on where 30 hours of TV lands on the normal curve. The tick marks on the x axis are one eviation in size. standard d b) What is the z-score for this problem? Use 2 decimals c) What is the probability a random woman would watch less than 30 hours of TV per week? Use four decimals.Explanation / Answer
b) Z score = (30-34)/4.5
= -0.89
c) P(X<30)
= P(Z<-0.89)
= 0.1870
e) Z score = (40-34)/4.5
= 1.33
f) P(X>40)
= P(Z>1.33)
= 0.0912
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