Question 1: Consider the following estimated model colGPA = 1.39 + .412 hsGPA +
ID: 3042598 • Letter: Q
Question
Question 1: Consider the following estimated model
colGPA = 1.39 + .412 hsGPA + .015 ACT - .083 Skipped
(.33) (.096) (.011) (.026)
n = 141
colGPA is college GPA in a 4 point scale, hsGPA is High School GPA, ACT is ACT score and Skipped is the average number of lectures missed each week.
What is the number of degrees of freedom in this case?
125
130
137
141
158
1936
Question 2: Consider the following estimated model
colGPA = 1.39 + .412 hsGPA + .015 ACT - .083 Skipped
(.33) (.096) (.011) (.026)
n = 141
colGPA is college GPA in a 4 point scale, hsGPA is High School GPA, ACT is ACT score and Skipped is the average number of lectures missed each week.What is the critical t value for a two tail test a the 95% confidence?
1.87
1.977
2.36
4.25
5.36
6.87
Question 3: Consider the following estimated model
colGPA = 1.39 + .412 hsGPA + .015 ACT - .083 Skipped
(.33) (.096) (.011) (.026)
n = 141
colGPA is college GPA in a 4 point scale, hsGPA is High School GPA, ACT is ACT score and Skipped is the average number of lectures missed each week.
What STATA command you use to calculate the critical t value for a two tail test at the 95% confidence?
di tprob(137, .95)
di invt(141, .975)
di invt(137, .95)
di invt(137, .975)
di tprob(137, .90)
di invt(141, .95)
Question 5: Consider the following estimated model
colGPA = 1.39 + .412 hsGPA + .015 ACT - .083 Skipped
(.33) (.096) (.011) (.026)
n = 141
colGPA is college GPA in a 4 point scale, hsGPA is High School GPA, ACT is ACT score and Skipped is the average number of lectures missed each week.
Is the coefficient on hsGPA statistically significant at the 95% confidence (two tail test)?
YES
NO
Question 6: Consider the following estimated model
colGPA = 1.39 + .412 hsGPA + .015 ACT - .083 Skipped
(.33) (.096) (.011) (.026)
n = 141
colGPA is college GPA in a 4 point scale, hsGPA is High School GPA, ACT is ACT score and Skipped is the average number of lectures missed each week.
What is the p-value of the hsGPA coefficient (two tail test)?
.0000234
.00356
.0231
.0985
.125
-.0254
Question 8
Consider the following estimated model
colGPA = 1.39 + .412 hsGPA + .015 ACT - .083 Skipped
(.33) (.096) (.011) (.026)
n = 141
colGPA is college GPA in a 4 point scale, hsGPA is High School GPA, ACT is ACT score and Skipped is the average number of lectures missed each week.
What is the t statistic on the ACT coefficient?
0.26
0.98
1.36
2.36
2.78
5.87
Question 9 Consider the following estimated model
colGPA = 1.39 + .412 hsGPA + .015 ACT - .083 Skipped
(.33) (.096) (.011) (.026)
n = 141
colGPA is college GPA in a 4 point scale, hsGPA is High School GPA, ACT is ACT score and Skipped is the average number of lectures missed each week.
Is the ACT coefficient statistically significant at the 90% confidence level (two tail test)?
YES
NO
Question 10: Consider the following estimated model
colGPA = 1.39 + .412 hsGPA + .015 ACT - .083 Skipped
(.33) (.096) (.011) (.026)
n = 141
colGPA is college GPA in a 4 point scale, hsGPA is High School GPA, ACT is ACT score and Skipped is the average number of lectures missed each week.
What is the p-value of the ACT coefficient (two tail test)?
.001
.069
.102
.176
.295
.387
125
130
137
141
158
1936
Question 2: Consider the following estimated model
colGPA = 1.39 + .412 hsGPA + .015 ACT - .083 Skipped
(.33) (.096) (.011) (.026)
n = 141
colGPA is college GPA in a 4 point scale, hsGPA is High School GPA, ACT is ACT score and Skipped is the average number of lectures missed each week.What is the critical t value for a two tail test a the 95% confidence?
1.87
1.977
2.36
4.25
5.36
6.87
Question 3: Consider the following estimated model
colGPA = 1.39 + .412 hsGPA + .015 ACT - .083 Skipped
(.33) (.096) (.011) (.026)
n = 141
colGPA is college GPA in a 4 point scale, hsGPA is High School GPA, ACT is ACT score and Skipped is the average number of lectures missed each week.
What STATA command you use to calculate the critical t value for a two tail test at the 95% confidence?
di tprob(137, .95)
di invt(141, .975)
di invt(137, .95)
di invt(137, .975)
di tprob(137, .90)
di invt(141, .95)
Question 5: Consider the following estimated model
colGPA = 1.39 + .412 hsGPA + .015 ACT - .083 Skipped
(.33) (.096) (.011) (.026)
n = 141
colGPA is college GPA in a 4 point scale, hsGPA is High School GPA, ACT is ACT score and Skipped is the average number of lectures missed each week.
Is the coefficient on hsGPA statistically significant at the 95% confidence (two tail test)?
YES
NO
Question 6: Consider the following estimated model
colGPA = 1.39 + .412 hsGPA + .015 ACT - .083 Skipped
(.33) (.096) (.011) (.026)
n = 141
colGPA is college GPA in a 4 point scale, hsGPA is High School GPA, ACT is ACT score and Skipped is the average number of lectures missed each week.
What is the p-value of the hsGPA coefficient (two tail test)?
.0000234
.00356
.0231
.0985
.125
-.0254
Question 8
Consider the following estimated model
colGPA = 1.39 + .412 hsGPA + .015 ACT - .083 Skipped
(.33) (.096) (.011) (.026)
n = 141
colGPA is college GPA in a 4 point scale, hsGPA is High School GPA, ACT is ACT score and Skipped is the average number of lectures missed each week.
What is the t statistic on the ACT coefficient?
0.26
0.98
1.36
2.36
2.78
5.87
Question 9 Consider the following estimated model
colGPA = 1.39 + .412 hsGPA + .015 ACT - .083 Skipped
(.33) (.096) (.011) (.026)
n = 141
colGPA is college GPA in a 4 point scale, hsGPA is High School GPA, ACT is ACT score and Skipped is the average number of lectures missed each week.
Is the ACT coefficient statistically significant at the 90% confidence level (two tail test)?
YES
NO
Question 10: Consider the following estimated model
colGPA = 1.39 + .412 hsGPA + .015 ACT - .083 Skipped
(.33) (.096) (.011) (.026)
n = 141
colGPA is college GPA in a 4 point scale, hsGPA is High School GPA, ACT is ACT score and Skipped is the average number of lectures missed each week.
What is the p-value of the ACT coefficient (two tail test)?
.001
.069
.102
.176
.295
.387
Explanation / Answer
1)
df = n-k-1
= 141 - 3-1
= 137
2) critical value for 95% confidence level with df = 137
= =T.INV.2T(0.05,137)
=1.977
3)
di invt(137, .95)
5)
TS = 0.412/0.096
= 4.29166 > 1.977
hence significant
YES
6) p-value =
=T.DIST.2T(0.412/0.096,137)
= 0.00003
option A)
8)
TS = 0.015/0.011
= 1.363636364
9)
p-value > 0.10
hence NO
10)
p-value = =T.DIST.2T(1.36363,137)
=0.176
Please rate i have solved them all
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