Moving On... 121 Look at the resulting histogram. It is generally mound-shaped,

Question

Moving On... 121 Look at the resulting histogram. It is generally mound-shaped, and therefore is acceptable for our purposes. Note that the histogram follows the normal curve relatively well. That being the case, we can proceed with the t test. If the distribution were not bell-shaped, we would need to use a nonparametric technique, described in Session 21. Analyze > Compare Means > One-Sample T-Test In the dialog box, select the variable Platelets, specify a hypothesized value of 3.9, and click OK. T-Test [DataSet2] D:DatasetsPheresis.sav One -Sample Statistics Std. Error One-Sample Test 95% condence interval of the Mean hatelet tield Remember that we must divide the reported significance level in half, since we want a 1-tailed test. On the basis of this test, what is your conclusion, assuming that = .05? Is the mean platelet yield greater than 3.9 x 1011P Is the Amicus machine more efficient than the other machine? Moving On... Now apply what you have learned in this session. You can use sample t tests for each of these questions. Report on the relevant test results, explain one- what you conclude from each test, and why. Comment he extent to which the normality assumption is satisfied for small samples.

Explanation / Answer

Here we have to test the hypothesis that,
H0 : mu = 3.9 * 1011 Vs H1 : mu > 3.9 * 1011  

where mu is the population mean.

Assume alpha = level of significance = 0.05

Given that,

sample size (n) = 13

sample mean (Xbar) = 4.0062

Sample standard deviation (s) = 0.50394

From all these values we get,

test statistic = 0.843

P-value = 0.412

We can see that,

P-value > alpha

Accept H0 at 5% level of signifcance.

Conclusion : The population mean may be 3.9 * 1011 .

Or we get insignificant result about one sample t-test.

The American machine is less efficient than the other machine.

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