Josh& General ChemistryI Chem102 Summer 2018 (Valley Center) 37 of 41 (> Previou

Question

Josh& General ChemistryI Chem102 Summer 2018 (Valley Center) 37 of 41 (> Previous Answers Correct This is the enthalpy change for the reaction that represents breaking the carbon-carbon bonds in benzene: Part D The answer is part C is the energy required to break six carbon-carbon bonds in benzene. Calculate the average bond enthalpy of one carbon-carbon bond in gaseous benzene,CHs(g) Express your answer to four significant figures and include the appropriate units. ? View Available Hintís) AH-Value Units Subrmit AM

Explanation / Answer

Answer-

As we know ,

structure of Benzene is

CH(g) --> C(g)+H(g)}, Delta H=413 kJ

so total energy for 6CH(g) = 6 x 413

=2478 kJ

Delta Hrxn = 5535.1 kJ ----for benzene which includes 6CH(g) and 6C-C(g) ( can be seen in the given structure )
so energy for  6C-C(g) =(5535.1-2478) kJ

=3057.1 kJ

so average energy for one C-C bond ( g) =3057.1/6

=509.5 kJ

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