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Internet and Computer Exercise 1 (From Marketing Research (6th Edition) ,Page 60

ID: 3042947 • Letter: I

Question

Internet and Computer Exercise 1 (From Marketing Research (6th Edition) ,Page 600: Chapter 18, Internet Exercise 1)- Conduct a two-group discriminant analysis on the data given in Tables 18.2 and 18.3 using SPSS (SAS and Minitab not needed). Compare the output and discuss similarities and differences. The comparison is about the similarities and differences in a) the significance values of the discriminant coefficients, b) percentage of original grouped cases correctly classified, and c) percentage of cross-validated grouped cases correctly classified across the three datasets.

no visit income travel vacation hhsize age amount 1 1 50.2 5 8 3 43 2 2 1 70.3 6 7 4 61 3 3 1 62.9 7 5 6 52 3 4 1 48.5 7 5 5 36 1 5 1 52.7 6 6 4 55 3 6 1 75 8 7 5 68 3 7 1 46.2 5 3 3 62 2 8 1 57 2 4 6 51 2 9 1 64.1 7 5 4 57 3 10 1 68.1 7 6 5 45 3 11 1 73.4 6 7 5 44 3 12 1 71.9 5 8 4 64 3 13 1 56.2 1 8 6 54 2 14 1 49.3 4 2 3 56 3 15 1 62 5 6 2 58 3 16 2 32.1 5 4 3 58 1 17 2 36.2 4 3 2 55 1 18 2 43.2 2 5 2 57 2 19 2 50.4 5 2 4 37 2 20 2 44.1 6 6 3 42 2 21 2 38.3 6 6 2 45 1 22 2 55 1 2 2 57 2 23 2 46.1 3 5 3 51 1 24 2 35 6 4 5 64 1 25 2 37.3 2 7 4 54 1 26 2 41.8 5 1 3 56 2 27 2 57 8 3 2 36 2 28 2 33.4 6 8 2 50 1 29 2 37.5 3 2 3 48 1 30 2 41.3 3 3 2 42 1 1 1 50.8 4 7 3 45 2 2 1 63.6 7 4 7 55 3 3 1 54 6 7 4 58 2 4 1 45 5 4 3 60 2 5 1 68 6 6 6 46 3 6 1 62.1 5 6 3 56 3 7 2 35 4 3 4 54 1 8 2 49.6 5 3 5 39 1 9 2 39.4 6 5 3 44 3 10 2 37 2 6 5 51 1 11 2 54.5 7 3 3 37 2 12 2 38.2 2 2 3 49 1

Explanation / Answer

Eigenvalues

Function

Eigenvalue

% of Variance

Cumulative %

Canonical Correlation

dimension0

1

1.925a

100.0

100.0

.811

a. First 1 canonical discriminant functions were used in the analysis.

1. The larger the eigenvalue, the more of the variance in the dependent variable is explained by that function.

. The canonical correlation is the measure of association between the discriminant function and the dependent variable.

Classification Function Coefficients

visit

1.00

2.00

income

.900

.765

travel

1.738

1.755

vacation

1.438

.860

hhsize

2.267

1.474

age

1.105

1.007

amount

-2.494

-4.678

(Constant)

-67.684

-45.821

Fisher's linear discriminant functions

Classification Resultsa

visit

Predicted Group Membership

Total

1.00

2.00

Original

Count

1.00

18

3

21

2.00

0

21

21

%

1.00

85.7

14.3

100.0

2.00

.0

100.0

100.0

a. 92.9% of original grouped cases correctly classified.

Test Results

Wilks' Lambda

Test of Function(s)

Wilks' Lambda

Chi-square

df

Sig.

dimension0

1

.342

39.714

6

.000

Wilks' lambda is a measure of how well each function separates cases into groups. Smaller values of Wilks' lambda indicate greater discriminatory ability of the function.

These all are the result of Discriminant analysis in SPSS.

a)the discriminant functions for 1 and 2 is

visit 1 =.9 Income+1.738 travel+1.438 vacation+2.267 hhsize+1.105age+-2.494 amount-67.684

Visit 2 =.765 Income+1.755travel+.860vacation+1.474hhsize+1.007 age+-4.678 amount-45.821

b) Originally classified =39/42

=.9285

Therefore percentage of originally classified =92%

Eigenvalues

Function

Eigenvalue

% of Variance

Cumulative %

Canonical Correlation

dimension0

1

1.925a

100.0

100.0

.811

a. First 1 canonical discriminant functions were used in the analysis.

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