Quiz: Quiz CH6 Time Remaining: 00:31:11 This Question: 1 pt 7017(4 complete) Thi

Question

Quiz: Quiz CH6 Time Remaining: 00:31:11 This Question: 1 pt 7017(4 complete) This Quiz: 7 pts The table below shows a relative-frequency distribution for the heights of lype an integer or a odecamal) female shudents at a midwestern college. The heights are approxiaelyhe normal diftribution approximates the percentage of fomale s normally distributed with mean 64.4 inches and standard deviation 1.8 12.71 %. with heights between 62 and 63 inches to be (Round to two decimal places as needed.) Height Frequency Relative frequency -(inches) The approximate percentage isless than the actual percenta 60-61 0.0099 0.0263 0.0954 0.2204 0.3191 0.2138 0.0888 00197 0.0066 61e62 62 63 6364 b. The percentage of female students with heights between 64 and 68 29 67 97 65 27 65e 66 66 67 67 c68 68-60 () The actual percentage of female students with heights between 64 a 68 inches is 63.84%, Type an integer or a decimal) (0) The normal distribution approximates the percentage of female stude with heights between 64 and 68 inches to Round to two decimal places as needed.) (i) The approom ate percentage iL the actual percentage, )More equal to ess tharn greater than Enter your answer in each of the answer boxes. Mathematics Ill - Redlands Unified School District aon l Using tho Normal Curve 1.1 sample a subset of the population sigma 0owe ease), a unt1-2 par

Explanation / Answer

b )

The actual % of female student with height 64 to 68 inches is,

=( 0.3191 + 0.2138 + 0.0888+ 0.0197 ) * 100

= 64.14%

ii) Using Normal distribution.

Mean = 64.4 , SD = 1.8

We have to find P( 64 < x < 68 )

P( 64 < x < 68 ) = P( x < 68 ) - P( x < 64 )

Using Excel function,   =NORMDIST( X, mean, SD , 1 )

P( x < 68 ) =NORMDIST(68,64.4,1.8,1) = 0.97725

P( x < 64 ) = NORMDIST(64,64.4,1.8,1) = 0.41207

So,

P( 64 < x < 68 ) = 0.97725 - 0.41207 = 0.56518

iii)

The approximate percentage is less than actual percentage.

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