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If X is a normal random varlable wh mean 5, and if the probabi Xs less than 5.63

ID: 3043511 • Letter: I

Question

If X is a normal random varlable wh mean 5, and if the probabi Xs less than 5.63 is 0.605 (as shown below, then what is the standard devlation of X?(Note: the diagram is not necessariy to scale.) 2.5535 22599 1.9662 3.5749 Let Z~NO.1).Find a Zo such that the area to the right otz Zo s 0.3557.(3 decimals) Number Find the probability P(-1 05 z 1.2) using the standard normal distribution 0.869 0.5024 0738 0.7754 A professional basketball player sinks 74.5% of his foul shots, in the long run I he gets 104 tries during a season, then the probabaity that he sinks between 66 and 93 shots inclusive) is approximatey equal to @-2.3448aZK 2.2706 Pl-2.52sZs 2.9374) OP2.8952 36041) Pl-3.2342 s Zs 4 7574) -2.9647s2x 4.1808) A series of independent rials are n ora in mial Process wit probability of success o he mean is four to b 5 and he a anceis at dy u e ir at tabe?

Explanation / Answer

1) Z for cumulative probability of 0.605 is 0.26631

Sigma = (5.68-5)/0.26631=2.5535

2) P( Z>z)=0.3557

Z = 0.3699 from normal tables

3) P(-1.05<z<1.2) = 1-0.11507 -0.146859=0.738

Stanard deviaton = sqrt(npq) = sqrt(104*0.745*0.255)=4.4449

np=104*0.745=77.48

Z= (93-77.48)/4.4449=3.6041

Hence, C is the right answer

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