i Partial table of areas under the standard normal curve 1 Second decimal place

Question

i Partial table of areas under the standard normal curve 1 Second decimal place in z z0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 2.00.9772 0.9778 0.9783 0.9788 0.9793 0.9798 0.9803 0.9808 0.9812 0.981 2.1 0.9821 0.9826 0.9830 0.9834 0.9838 0.9842 0.9846 0.9850 0.9854 0.985 2.2 0.9861 0.9864 0.9868 0.9871 0.9875 0.9878 0.9881 0.9884 0.9887 0.9890 2.3 0.9893 0.9896 0.9898 0.9901 0.9904 0.9906 0.9909 0.9911 0.9913 0.991 2.4 0.9918 0.9920 0.9922 0.9925 0.9927 0.9929 0.9931 0.9932 0.9934 0.993 Print Done

Explanation / Answer

Since the given test is a left - tailed test,

P - value = P(z < 2.20) = 0.9861

Does not provide; greater than

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