question 5. is my solution correct? if not what is? Thank you a. exactly one ace
ID: 3044378 • Letter: Q
Question
question 5. is my solution correct? if not what is? Thank you
a. exactly one ace; b. at least one ace? Problem 5 Five cards are dealt from a shuffled deck. What is the probability that the dealt hand contains exactly two aces, given that we know it contains at least one ace? Problem 6 The 52 cards in a shuffled deck are dealt equally among four players, call them A, B, C, and D. If A and B have exactly 7 spades, what is the probability that C has exactly 4 spades? Problem 7 There are 50 students in a class and the professor chooses 15 students at random. What is theExplanation / Answer
5) Solution:
Probability of being dealt at least one ace could mean 1, 2, 3, or 4
aces. This is best calculated from 1 - Prob(no aces)
Prob(no aces) = C(48,5)/C(52,5) = 0.658842
Probability of at least one ace = 0.341158
Prob(2 aces|at least one ace) = C(4,2) x C(48,3)/0.341158 x C(52,5)
= 0.11704
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