Question8 The ground state electron configuration of Ga is 1s22s23s23p64523d104p

Question

Question8 The ground state electron configuration of Ga is 1s22s23s23p64523d104p1 1s22s22p63s23p64524d104p1 1s22s22p63s23p64s23d104p1 1s22s22p63523p64s23d104d1 [Ar)4s23d11 Question 9 Which one of the following is a metalloid? ?Ge O S O Pb Question 10 Which equation correctly represents the first ionization of copper? Cu(g) cut (g) + e- ? Cu (g) ? Cu" (g) + e- Cu (g) + e-? Cu" (g) OCu" (g) ? Cu(g) + e. cut (g) + e-? Cu(g) Question 11 Which of the following correctly represents the second ionization of calcium? Ca(g) ? Ca+ (g) + e- o cat (g) ? Ca2+ (g) + e- ocat (g) + e-? Ca2+ (g) oct (g) + e-? Ca(g) Question 12 Which equation correctly represents the first ionization of aluminum? A" (g) ? Al (g) + e- OAI (g) ? Ar (g) + e- Al (g) + e-? Al-(g) OAI (g) ? Ajt (g) + e- OA + (g) + e-?Al(g)

Explanation / Answer

Answer:

(8) Galium: Atomic number=31.

The electronic configuration of Ga is

1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^1

The orbitals are filled according to the Aufbau priciple.

So 3rd option is correct.

(9) Mettaloid is Germanium (Ge). It has properties which make it as metal like or some properties are make them like non-metal.

Carbon (C), Bromine (Br), Sulfur (S) are non metals and lead (Pb) is metal.

First option is correct.

(10) The energy released when the element loose one electron is called first ionisation energy.

For Copper, Cu(g) --------> Cu^+(g) + e^-

First option is correct.

(11) The removal of one more electron from first ion is second ionization.

Ca^+ (g) ------------> Ca^+2 + e^-

Second option is correct.

(12) First ionization of Al is similar to copper in problem 10.

Al(g) --------> Al^+(g) + e^-

4th option is correct.

Please let me know if you have any doubt. Thanks and I hope you like it.

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