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Please help to solve the question using formulas without using r, thank you! 8.

ID: 3044668 • Letter: P

Question

Please help to solve the question using formulas without using r, thank you!

8. (20pts) Consider the following questions: give the distribution name, carefully define the random variables you use and find the final answer. (a) (4pts) A professor has made 20 exams of which 8 are hard, 7 are reasonable, and 5 are easy. The exams are mixed up and the professor selects 4 of them at random to give to four sections of the course she is teaching. What is the probability that no sections receive a hard test? (b) (4pts) Suppose a representative at a credit card customer service center receives a phone call every 5 minutes on average. Find the probability that she receives 3 phone calls in 20 minutes. (c) (4pts) Products produced by a machine has a 3% defective rate. what is the probability that the first defective occurs in the fifth item inspected. (d) (4pts) In a class of 100 students, 25 have hardcover and 75 students have paperback textbooks. If you randomly choose 10 students in this class, find the probability that 2 of them have hardcover texts. (e) (4pts) Emily hits 60% of her free throws in basketball games. She had 7 free throws in last week's game. What is the probability that she made at least 5 hits?

Explanation / Answer

a)Binomial Distribution
Random variable x is the number of hard tests selected

4 non hard test can be selected from 12 tests, this can be done in 12C4 ways

Required probability = 12C4/20C4 = 0.1022

b) Poisson's Distribution
Random variable x is the number of phone calls received

lambda = 1/5 * 20 = 4

P(X = 3) = e^(-4)*4^3/3! = 0.1954


c) Negative Binomial Distribution
Random variable x is the first occurrance of success

P(X = 5) = (1-0.03)^4 * (0.03) = 0.0266

d) Binomial Distribution
Random variable x is the number of students with hardcover text

p = 25/100 = 0.25

P(X = 2) = 10C2 * 0.25^2 * 0.75^8 = 0.2816

e) Binomial Distribution
Random variable x is the number of hits

p = 0.6

P(X >= 5) = 7C5 * 0.6^5 * 0.4^2 + 7C6 * 0.6^6 * 0.4^1 + 7C7 * 0.6^7 * 0.4^0 = 0.4199

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