ACS Exams period on the periodic table because (A) the effective nuclear charge
ID: 304536 • Letter: A
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ACS Exams period on the periodic table because (A) the effective nuclear charge increases attracting the 22. The atomic radius decreases from left to right across 16. What is the energy of a photon with a wavelength (@) of 486 nm (A) 3.22x10J (C) 1.07x10" Which is an allowed set of quantum numbers for a 4d (B) 40910», (D) 4.09x10-"J the electrons begin to be paired within the valence orbitals valence electrons more strongly (B) (C) the electrons end up occupying core orbitals, which (D) the nucleus begins to shrink as the number of 17. are smaller clectron in the ground state of cadmium? nmm protons increases (A) 4 22+ 23. Which ion has the largest radius? (1B) (A) F (B) Mg (C) Na (D) * -3 Which third period [Ionization Energy/kJ-mor 24. 578 1817 2745 11577 (D) 4 30 element has the successive ionization energies (IE) given in this table? IE(2) 1E(3) 18. The energy of an electron in a malti-electrom atom is determined by (A) the principle quantum mumber, n, only (B) the angular momestum quantum number, t, ony (C) the principle and angular momentum quantum Al (B) Mg (C) Na (D) Si (A) Which atom has the largest first ionization energy? (A) Mg How many nonbonding pairs of electrons are on the 25. numbers, n and t (B) S (C) Si (D) Sr (D) the principle, angular momestum and magnetic quantum numbers, n, t, and m, 26. central atom in BrF,? (A) 0(B)1 Which species is not planar? (A) 19. To what cloment does this orbital diagrans comespond? (C) 2 (D) 3 1s 2s 2p 3s 3p 27. (A) Br (B) C (C) Mn (D) P BF, (B) CI, (C) PF, NO (D) 28. What is the molecular geometry of the CIF ion? (B) square planar 20. What is the ground state electron configuration of the Mn loa? (C) [ArHs'sd for its valence electrons (B) [Arl4s'3d (D) [ArAsd (A) seesaw (C) square pyramidal (D) tetrabedral Which molecule has a tetrabedral geometry about the central atom? 21. Which atom has the highest effective nuclear charge, s 29. (A) SiF (B) PF (C) According to the VSEPR method, what are the approximate values of the bond angles X and Y? SF (D) XeF. 30. HC--ö (A) X is 90 and Y is 90 (B) X is 90 and Y is 109.5 (C) X is 109.5° and Y is 90 (D) X is 109.5° and Y is 109.5? O ACS DivCHED Examinations Institute Illegal to copy, photerroExplanation / Answer
16: B-4.09*10-28
->E=hv=hc/?
h= planck's constant=6.626x10-34
C=3x108ms-1
?=486 nm
=>(626*10-34*3*108)/486
4.0909123457*10-28
17: A
18: B
19: B
20: A
21: D-s
Zeff=Z-S
z=atomic number
s=inner core electrons
-Ca=0-18=+2
-Mg=12-10=+2
-p=15-10=+5
-s=16-10=+6
22:A
23:D
F=.133
Mg2+=.072
Na+=.102
O2-=.140
24: A
25: B
26:C
27: C
28:A
29:A
30: D
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