Question 9 a) (4 points) For the reaction 2 A(aB(a)C (aq), the concentrations at

Question

Question 9 a) (4 points) For the reaction 2 A(aB(a)C (aq), the concentrations at equilibrium of A (aq), B(aq) and C(aq) are respectively 0.277 M, 0.322 M and 0.411 M. What is the value of AG° for this reaction? When the system is in equilibrium, we add A(aq) until its concentration becomes 0.611 M. What is the value of ?G at that instant. The temperature remains 25.0°C (4 points) In the reaction 3 A(g) equilibrium. At equilibrium, the total pressure is 8.00 atm, and the partial pressure of B(g) is 1.50 atm. what is the value of ?G° for this reaction? The temperature remains 25.0°C. b) 2B(g) + 4C (g), we start with only pure A(g). We reach

Explanation / Answer

1) For the reaction:

2A = B + C

we have a K = [B] * [C] / [A] ^ 2 we substitute the values ??and we have:

K = (0.322) * (0.411) / (0.277) ^ 2 = 1.725

The ?G = -RT * Ln (K) is then calculated

?G = - 8.314 * 298 * Ln (1.725) = - 1350.84 J / mol

2) For the reaction:

3A = 2B + 4C

we have:

Pa = x - 3y

Pb = 2y = 1.5 atm

Pc = 4y

clearing and of Pb we have:

y = 1.5 atm / 2 = 0.75 atm and we substitute Y in the partial pressures:

Pb = 1.5 atm

Pc = 3 atm

Pa = 8 - 1.5 - 3 = 3.5 atm

we calculate K = Pb ^ 2 * Pc ^ 4 / Pa ^ 3

K = (1.5) ^ 2 * (3) ^ 4 / (3.5) ^ 3 = 4.251

and finally we find out:

?G = - 8.314 * 298 * Ln (4.251) = -3585.43 J / mol.

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