I need help with 5 d i safari File Edit View History Bookmarks Window Help 14% D

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I need help with 5 d

i safari File Edit View History Bookmarks Window Help 14% D' Mon 8:52 AM webass gn.net Close Your disk is almost full Mai HW2 ID t 0Mail Request Chegg Tu Save space by optimizing storage Manage Azzam Abbas IRS Azzam Need Help? Read ItTalk to a Tutor 1.. .2016.pdf Signatur...2016.pdf IEP-Exemption- Form 3 5· 3/4 points A box in a supply room contains 23 compact fluorescent lightbulbs, of which 8 are rated 13-watt, 9 are rated 18-watt, and 6 are rated 23-watt. Suppose that three of these bulbs are randomly selected. (Round your answers to three decimal places.) | Previous Answers DevoreStat92.E·039. My Notes Ask Your T ÷ (a) What is the probability that exactly two of the selected bulbs are rated 23-watt? 144 document.pdf (b) What is the probability that all three of the bulbs have the same rating? 09034 362 Spring2 HW 3a.docx (c) What is the probability that one bulb of each type is selected? 244 Code Composer (d) If bulbs are selected one by one until a 23-watt bulb is obtained, what is the probability that it is necessary to examine at least 6 bulbs? 7794 hw 4 DFCQ Read It Talk to a Tutor hw2.docx problem 5 6. 4/4 points| Previous Answers DevoreStat9 2.E.048. My Notes Ask Your Teacher A certain system can experience three different types of defects. Let A, (i = 1,2,3) denote the event that the system has a defect of type i. Suppose that the following probabilities are true. PCA.) = 0.11 Paz) = 0.07 P(As) = 0.05 RA, U Az) = 0.12 Ai UAs) = 0.13 RA2 U As) = 0.10 A1 n A2 n A3) = 0.01 Shot 8-02. 1.24 AM 19

Explanation / Answer

(d) answer is 0.0576

since 6 bulb is selected one by one, it means upto 5th draw bulb there is not any 23 watt bulb is selected and in the 6th draw 23 watt is selected

P( 23 watt bulbs is selected)=6/23

P(23 watt bulbs is not selected)=1-P( 23 watt bulbs is selected)=1- 6/23=17/23

required probability of 23 watt will be selected at 6th draw =(17/23)5(6/23)=0.2206*0.2609=0.0576

alternatively here we can use geometric distribution with p=6/23 and x=5

P(X=x)=(1-p)x-1p

P(X=6)=(1-6/23)6-1(6/23)=(17/23)5(6/23)=0.2206*0.2609=0.0576

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