A pharmaceutical company is testing a new drug to increase memorization ability.
ID: 3047008 • Letter: A
Question
A pharmaceutical company is testing a new drug to increase memorization ability. It takes a sample of individuals and splits them randomly into two groups. After the drug regimen is completed, all members of the study are given a test for memorization ability with higher scores representing a better ability to memorize. Those 20 participants on the drug had an average test score of 31.666 (SD = 3.221), while those 23 participants not on the drug had an average score of 41.32 (SD = 6.838). You use this information to create a 90% confidence interval for the difference in average test score of (-12.468, -6.84). Which of the following is the best interpretation of this interval?
1) We are 90% confident that the difference between the average test score of people who would take drug in the study and people not on the drug in the study is between -12.468 and -6.84.
2) We are certain that the difference between the average test score of all people who would take drug and all people not taking the drug is between -12.468 and -6.84.
3) We are 90% confident that the difference between the average test score of all people who would take drug and all people not taking the drug is between -12.468 and -6.84.
4) We do not know the population means so we do not have enough information to make an interpretation.
5) We are 90% sure that the average difference in test score of all people who would take the drug and people not on the drug in the state the study was completed in is between -12.468 and -6.84.
A new drug to treat high cholesterol is being tested by pharmaceutical company. The cholesterol levels for 25 patients were recorded before administering the drug and after. The mean difference in total cholesterol levels (after - before) was -17.839 mg/dL with a standard deviation of 9.438 mg/dL. When creating a 90% confidence interval for the true average difference in cholesterol levels by the drug, what is the margin of error?
1) 3.2295
2) 3.2243
3) 1.8876
4) 0.7049
5) 2.4847
Explanation / Answer
1)option 3 is correct
3) We are 90% confident that the difference between the average test score of all people who would take drug and all people not taking the drug is between -12.468 and -6.84.
2)for (n-1=24) degree of freedom and 90% Ci l;crtiical t =1.7109
std error =std deviation/(n)1/2 =9.438/(25)1/2 =1.8876
margin of error =t*Std error =3.2295
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