A small advertising agency has eight employees, six men and two women. The firm

Question

A small advertising agency has eight employees, six men and two women. The firm has three clients that are difficult to deal with. To decide who of the employees of the agency serves the first customer, one of the eight is selected randomly. Also selected randomly the one who will serve the second client and likewise who will attend the third client.
a) Obtain the probability that the three clients will be served by the same person.
b) Obtain the probability that all three clients are attended only by men.

Explanation / Answer

a) P(3 calls will be served by the same person) = (1/8)3

= 0.00195

b) P(all three clients are attended by men) = (6/8)3

= 0.4219

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