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The United States Golf Association requires that the weight of a golf ball must

ID: 3047365 • Letter: T

Question

The United States Golf Association requires that the weight of a golf ball must not exceed 1.62 oz. The association periodically checks golf balls sold in the United States by sampling specific brands stocked by pro shops. Suppose oz. in weight. Suppose that 24 of this manufacturer's golf bals are randomly selected, and let x denote the number of the 24 randomly selected golf balls that exceed 1.62 oz. Refer to the Binomial table given below. Excel Output of the Binomial Distribution with n = 24, p-0.11, and q = 0.89 Binomial distribution with n 24 and p 0.11 Poex) 0.0810 0.1810 0.2572 0.2331 0.1513 0.0743 (a Find P -o), hat is find the probabi y that none of he random y selected golf bals exceeds 62 oz n weight. Use table valu e rounded t 4 decima places or calculations. Round your ans ver o·decimal plac P/x-0) (b) Find the probability that at least one of the randomly selected golf balls exceeds 1.62 oz. in weight. (Use table values rounded to 4 decimal places for calculations. Round your answer to 4 decimal places.) Pix 1) (c) Find Px 3). (Use table values rounded to 4 decimal places for calculations. Round your answer to 4 decimal places.) P(x s3) (d) Find Pix 2 2). (Use table values rounded to 4 decimal places for calculations. Round your answer to 4 decimal places.) P(x 2 2) (e Suppose hat 2 of the 24 random y selected golf balls are found to exceed 1 62 oz usng your resu rom a t do you believe he claimt at no more th 11 percentof is rand of olfbals exceed 620 n weight (Click to select)the probabity of this resultis Click to select) if the claim is true.

Explanation / Answer

Given that,

n=24, and p=0.11

a) P(x=0)=0.0610

b)P(x>=1) = 1 - P(x=0)

= 1 - 0.0610

P(x>=1) = 0.9390

C) P(x<=3) = P(x=0)+P(x=1)+p(x=2)+p(x=3)

= 0.0610+0.1810+0.2572+0.2331

P(x<=3) = 0.7323

d) P(x>=2) = 1 - P(x<2)

= 1 - {P(x=0)+P(x=1)}

= 1 - { 0.0610 + 0.1810}

P(x>=2) = 0.7580

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