Let \"Z\" be a random variable from the standard normal distribution. Find the v

Question

Let "Z" be a random variable from the standard normal distribution. Find the value for ? that satisfies each of the following probabilities.

(Round all answers to two decimal places)

A) P(Z < ?) = 0.7083.
    ? =  

B) P(Z > ?) = 0.8837.
    ? =  

C) P(-? < Z < ?) = 0.6448.
    ? = ±

8. 15 points y Notes Let "Z" be a random variable from the standard normal distribution. Find the value for ? that satisfies each of the following probablities (Round all answers to two decimal places) A) P(z

Explanation / Answer

A)

Using excel function, "=NORMSINV(0.7083)" the required z-score is 0.55.

That is

(Z < 0.55) = 0.7083

B)

Here we need z-score that has 1 - 0.8837 = 0.1163 area to its left. Using excel function, "=NORMSINV(0.1163)" the required z-score is -1.19.

That is

(Z > -1.19) = 0.8837

C)

Here we need z-scores that has 0.6448 area between them. That is z-scores that has (1-0.6448) /2 = 0.1776 area at both tails.

Using excel function, "=NORMSINV(0.1776)" the required z-score is -0.92.

So

z = +/- 0.92

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