Statistice Training 21. Neferto Table ,\" You are interviewiasE peoplebrakb from

Question

Statistice Training 21. Neferto Table ," You are interviewiasE peoplebrakb froms this population at randomm, what io the probsbälltying that they have n 3730 P(MAS) 8064 22. Refer to Table 1. You are isterviewing people for a job opening. If a person from this population at randomm, what is the probability that they have statisdelectea or no management training? (S 5161 4800 23. Refer to Table 1. You are interviewing people for a job opening. If a person is selected from this population at random, what is the probability that they have no management training given that they have no statistics training? 1129 5833 1892 24. Refer to Table 1. Which statement best describes management and statistics training? Statistics and management training are mutually ecclusive and independent Statisti ies and management training are mutually exclusive and not independent. Statistics and Statistics and management training are sot motually exclusive and are not indepenident. 25. The probability that a college student is under 23 and living at home is .35. The probability that a college student is under 23 is .75. The probability that a student is 23 or over is .25. The probability that a student lives at home is .55. The probability they do not is 45. What is the probability that a student lives at home or is under 23 years old? .70 b. 90 .95

Explanation / Answer

21 and 22 are correct

23 logic is correct, however value of M' = 75 and not 50. Thus, answer has to be 75/375

the answers 21 to 23 are bit different but will be accurate if you consider 70 instead of 75 throughout and recalculate

Here it will be 70/370 = 0.1892

24) Independent if P(x)P(y) = P(x and y) for all x and y

P(S) = 250/620

P(M) = 500/620

P(S)*P(M) = 250/620 * 500/620 = 0.3251

P(S and M) = 200/620 = 0.3225

Hence, not independent

25)

P(home or under 23) = P(home) + P(under 23) - P(home and under 23)

= 0.55 + 0.75 - 0.35

= 0.95

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