Question 1 An interval that includes a certain proportion of measurements with a

Question

Question 1

An interval that includes a certain proportion of measurements with a stated confidence is called a:

Question 2

For table 8-2: Set up a 95 % confidence interval estimate of the population average (2-sided). High-end =

Question 3

For table 8-2: Set up a 99 % confidence interval estimate of the population average (2-sided). Provide the t-value being used =

Question 4

For table 8-2: Set up a 95 % confidence interval estimate of the population standard deviation (2-sided). Provide the Low-end sigma-value =

Question 5

For table 8-6: Set up a 95 % confidence interval estimate of the population standard deviation (2-sided). Provide the Chi^2-value used in that calculation for the low end sigma.

Question 6

For table 8-6: Set up a 99 % prediction interval estimate of individual future data points (2-sided). High-end =

Question 7

For table 8-5: Set up a 99 % prediction interval estimate of individual future data points (2-sided). Provide the t-value being used =

Question 8

For table 8-2: Set up a 99 % tolerance estimate that will include 90% of the data points (2-sided). Low-end =

Question 9

For Table 8-6: Set up a 95 % tolerance estimate that will be exceeded by 99% of the data points. Provide the K-value being used =

Question 10

For Table 8-T2: Calculate the 95 % confidence interval estimate for the proportion of right-sided adults relative to the entire sea otter population (2-sided). Low-end =

Table 8-1

Table 8-2

13

Table 8-3

Table 8-4

Table 8-5

Table 8-6

Table 8-T1

Table 8-T2

Table 8-T3

Table 8-T4

a) tolerance interval

Explanation / Answer

#1.
An interval that includes a certain proportion of measurements with a stated confidence is called a Confidence interval (option C)

#2.

High end = 16.9217

#3.

n = 75
CI = 99%
t-value = 2.6439 (here df = 75-1 = 74)

This value is calculated using excel formula : =T.INV(0.005, 74)*-1

#4.

In question #2, standard error is calculated as 0.57913 and the estimated standard deviation is used 5.0154

CI for 95% n 75 mean 15.78666667 z-value of 95% CI 1.9600 std. dev. 5.015425096 SE = std.dev./sqrt(n) 0.57913 ME = z*SE 1.13508 Lower Limit = Mean - ME 14.65159 Upper Limit = Mean + ME 16.92174 95% CI (14.6516 , 16.9217 )

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