In a test of a gender-selection method, 14 babies are born and 10 of them are gi

Question

In a test of a gender-selection method, 14 babies are born and 10 of them are girls. 1) Find the number of different possible sequences of genders that are possible when 14 babies are born. 2) How many ways can 10 girls and 4 boys be arranged in a sequence. 3) If 14 babies are randomly selected, what is the probability that they consist of 10 girls and 4 boys?
In a test of a gender-selection method, 14 babies are born and 10 of them are girls. 1) Find the number of different possible sequences of genders that are possible when 14 babies are born. 2) How many ways can 10 girls and 4 boys be arranged in a sequence. 3) If 14 babies are randomly selected, what is the probability that they consist of 10 girls and 4 boys?
In a test of a gender-selection method, 14 babies are born and 10 of them are girls. 1) Find the number of different possible sequences of genders that are possible when 14 babies are born. 2) How many ways can 10 girls and 4 boys be arranged in a sequence. 3) If 14 babies are randomly selected, what is the probability that they consist of 10 girls and 4 boys?

Explanation / Answer

1) No different different possible sequences of genders = 2^14 = 16384

2) No of ways to arrange 10 girls and 4 boys = 14!/(10! * 4!) = 1001

3) Probability = (14!/(4! * 10!)/2^14 = 0.061

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