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2-PSY 212 Multiple Choice Idenrify she Yow choice shat best compietes the statem

ID: 3048977 • Letter: 2

Question

2-PSY 212 Multiple Choice Idenrify she Yow choice shat best compietes the statement or answers the question. Mark your choice on a blue Scantron fo form within may write on the t est paper, but credit will be awarded only for correct answers marked on the Scantron the time liit 1. A vertical line is drawn through a normal distribution at z 1.20. What proportion of the di the left-hand side of the line? c. 0.8849 d. 0.7698 a 0.1151 b. 0.3849 -2. lfthese same scores were a population, then the SS value for the A sample of n = 8 scores has SS s 50. population would be 50 b. less than 50 e. greater than 50 d. This is impossible to determine without additional information. what proportion of a normal distribution is located between z =-0.25 and z = +0.25? a 0.0987 b. 0.4013 3. _ c. 0.5987 d. 0.1974 If the sample mean is M A sample of n 34, then what is the z-score for the sample mean? a. z=0.25 b, 4. 1 6 scores is obtained from a population with -50 and -16. _ c, z=1.00 d. z 4.00 z=0.50 5. which value for the standard deviation would giv On an etam with -52. you have a score of X-44, the highest position in the class distribution? d. It cannot be determined from the information given. 6. 20 what score separates the highest 40% of the A normal distnbution has amean of distribution from the rest of the scores? X=54.4 b, X=85 80 witho d. X=105.6 7· For a sample with M = 80, a score of X-88 corresponds to 2.00, what is the sample standard d b. 4 c. d. 16 8. A sample of n 4 scores is obtained from a population with 70 and -8. If the sample mean corresponds to a z-score of 2.00, then what is the value of the sample mean? a, M=86 b, c, M=74 M=78 d, M=72 9. What is the probability of randomly selecting a z-score less than z 1.25 from a normal distributie a. 0.2112 b. 0.3944 c. 0.1056 d. 0.8944

Explanation / Answer

Solution:-
1. option c. 0.8849
Explanation : 50.00+33.49=0.8849

2. option a. 50

3. option d. 0.1974
=> P (0.25<Z<0.25 )=0.1974

4. option c. Z = 1.00
=> Z = (54 - 50)/(16/sqrt(16)) = 1

5. option c. standard deviation = 8

6. option b. X = 85

7. option b. 4
=>Explanation = (88 - 80)/sd = 2 => sd = 8/2 = 4

8. option b. M = 78

9. option d. 0.8944
=> P ( Z<1.25 )=0.8944

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