A therapist treating clients for communicating apprehension (fear of public spea

Question

A therapist treating clients for communicating apprehension (fear of public speaking) assessed the effectiveness of the treatment by giving her clients a standard test at the beginning and the end of the treatment. The difference between the two scores was an indication of change. Here are the scores (a negative score indicates improvement):

If the treatment produced no effect the change score would be 0, so assume that the population mean is 0. Test the null using alpha .05. Did the treatment significantly reduce communication apprehension? Do all 7 steps.

Explanation / Answer

Step : 1 H0 : There is no improvement in the communication apprehension by the treatment. d = 0

Ha : There is a significant improvement in the communcation apprehnsion by the treatment. d > 0

Step 2 : Significance level alpha = 0.05

Step 3 : critical test statistics value; dF = 12 and alpha = 0.05

tcritical = 1.7823

Step 4 :

Assumptions and conditions :

Step 5 : Test statistic

Here difference of sample, dbar = -1.8462

standard deviation sd = 4.2982

Standard error of differece sed = sd/sqrt(n) = 4.2982/ sqrt(13) = 1.1921

Test statistics

t = dbar / sed = -1.8462/1.1921 = -1.5487

Step 6 : Here,

l t l < tcritical So we failed to reject the null hypothesis (H0)

Step 7 : Here we can conclude that There is no improvement in the communication apprehension (fear of public speaking) by the treatment.

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