Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Need help answering and understanding #1&2 and how they got the answer please. I

ID: 3051133 • Letter: N

Question

Need help answering and understanding #1&2 and how they got the answer please. Instructor Valljo STATS XLI0 Solve the problem. 1) The National Center for Health Statistics has found that there is a 5.01% chance that an 1) American citizen will die from an accident (unintentional injury). What is the probability that you will not die from an accident? (Round to the nearest hundredth of a percent) A) 99.50% B) Can't be determined with the given information. C) 94.99% D) 95.00% Find the indicated probability. 2) The Book Industry Study Group, Inc, performs sample surveys to obtain information on 2) characteristics of book readers. A book reader is defined to be one who read one or more books in the six months prior to the survey; a non-book reader is defined to be one who read newspapers or magazines but no books in the six months prior to the survey; a nonreader is defined to be one who did not read a book, newspaper, or magazine in the six months prior to the survey The following data were obtained from a random sample of people 16 years old and over Classfication Book Non-book Non- Total reader reader reader Less than| 173 | 267 | 55 495 $15,000 Household $15,000 to Income $24,999 131 149 25 305 $25,000 to $39,999 156| 146 | 11 313 $40,000 and over 213 85 5 303 673 64796 1,416 Suppose one of these people is selected at random. Compute the probability that the D) 0.111 person is a nonreader A) 0.573 B) 0.068 C) 0.039

Explanation / Answer

1) P(one will not die with accident) =100-P(one will die with accident) (as there are complemetary events)

=100-5.01 =94.99%

option C

2)

P(non reader) =96/1416=0.068 (as there are 96 non reader out of total 1416

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote