es University-MTH 150 C … Peggy Sultan omework: Homework 6A ore: 0 of 1 pt 3.21

Question

es University-MTH 150 C … Peggy Sultan omework: Homework 6A ore: 0 of 1 pt 3.21 A survey found that women's heights are nomaly dastibuted with mean 63.7 in and standard devian23 in. A branch of the miltary nequires women's heights to be between 58 in and 80 in 28of32(23 complete) a Find the pencentage of women meeting the height equiremert Are many wonen being denied the opportunity to join this branch of the mitary because they are too short or toota? Round to two deima places as needed) W E caps ok control option command comwvandophion

Explanation / Answer

a)

therefore % of those meeting height requirement =

b)

for shortest 1 % ; z score =-2.3263

threfore corresponding height =mean +z*std deviation =58.35

for longest 2 % ; z score =-2.0537

threfore corresponding height =mean +z*std deviation =68.42

hence range must be from 58.3 to 68.4

for normal distribution z score =(X-)/ here mean=       = 63.700 std deviation   == 2.3

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