2. -12.5 points MBasicStat7 12.E.008 My Notes Ask Your Teacher In many settings,
ID: 3051440 • Letter: 2
Question
2. -12.5 points MBasicStat7 12.E.008 My Notes Ask Your Teacher In many settings, the "rules of probability" are just basic facts about percents. The Graduate Management Admission Test (GMAT) website provides the following information about the geographic regions of those who took the test in 2012-13: 2.3% were from Africa; 0.5% were from Australia and the Pacific Islands: 2.7% were from Canada; 11.5% were from Central and South Asia: 29.1% were from East and Southeast Asia; 2.1% were from Eastern Europe; 2.8% were from Mexico, the Caribbean, and Latin America: 3.6% were from the Middle East 38.0% were from the United States; and 7.4% were from western Europe (a) What percent of those who took the test in 2012-13 were from North America (either Canada, the United States, Mexico, the Caribbean, or Latin America)? (Enter your answer to one decimal place.) True or False: This assignment of probabilities to student backgrounds (the percentage of those who took the test in 2012-2013 who were from North America) makes use of Rule 3 of the Probability Rules. (Rule3tates: Two events A and B are disjoint if they have no outcomes in common and so can never occur together. If A and B are disjoint, P(A or B) PA) P(B).) O True O False (b) What percent of those who took the test in 2012-13 were from some other region than the United States? (Enter your answer to one decimal place.) True or False: This assignment of probabilities to student backgrounds (the percentage of those who took the test in 2012-2013 who were from some other region than the United States) makes use of Rule 3 of the Probability Rules. (Rule 3 states: Two events A and B are disjoint if they have no outcomes in common and so can never occur together. If A and B are disjoint, P(A or B)-P(A) P(B).) O True O FalseExplanation / Answer
a)Percentage of students who took the test in 2012-13 were from North America(Canada, USA,Mexico, Carribean, Latin America)
Perentage=2.7+38+2.8=43.5%
Two events A and B are disjoint if they have no outcomes in common ie,
P(A or B)=P(A)+P(B)
The assignment of probabilities makes use of Rule 3 of probability Rules. Answer is True
b) Percentage of students who took the test in 2012-13 were from some other region than United States=
2.3+0.5+2.7+11.5+29.1+2.1+2.8+3.6+ 7.4=62%
Two events A and B are disjoint if they have no outcomes in common ie,
P(A or B)=P(A)+P(B)
The assignment of probabilities makes use of Rule 3 of probability Rules. Answer is True
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.