Note: Answer the Question(s) by Using the TI-30XA (or other approved) Calculator

Question

Note: Answer the Question(s) by Using the TI-30XA (or other approved) Calculator. IMPORTANT: Make sure you carry all decimals until you reach your answer, then round to four decimals. A recent survey showed that 63% of U.S. employers were likely to require higher employee contributions for health care coverage. Suppose the survey was based on a sample of 600 companies. Find the 95% confidence interval for the proportion of all companies likely to require higher employee contributions for health care coverage. (See exercise 40 on page 370 of your textbook for a similar problem.) Left Endpoint Right Endpoint

Explanation / Answer

Normal approximation to the binomial calculation:

Standard error of the mean = SEM = x(N-x)/N3 = 0.020

= (1-CL)/2 = 0.025

Standard normal deviate for = Z = 1.960

Proportion of positive results = P = x/N = 0.630

Lower bound = P - (Z*SEM) = 0.591

Upper bound = P + (Z*SEM) = 0.669

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