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(06.05 LC) At a large university, 20% of a random sample of male students have a

ID: 3052038 • Letter: #

Question

(06.05 LC) At a large university, 20% of a random sample of male students have an overall grade point average (GPA) of 3.5 or higher. A random sample of female student records found that 25% had a GPA of 3.5 or higher. The president of the university wants to determine whether there is evidence of a difference in grades between males and females. What would she write as the null and alternative hypotheses for this situation? (4 points) O Ho:p1-P2-0 and Ha:P1-P2 # 0 Ho:P1 P2 0 and Ha:p1 P2>0 Ho:p1-P2 = 0 and Ha: p1-p2 0 and Ha:P1-P2 = 0 Ho: p2>0 and Ha:pp20

Explanation / Answer

5) z = 0.93

P-value = 2 * P(Z > 0.93)

             = 2 * (1 - P(Z < 0.93))

             = 2 * (1 - 0.8238)

             = 2 * 0.1762

             = 0.3524

4) At alpha = 0.05, the critical value is z0.025 = +/- 1.96

As z = 2.2 doesn't lie between the critical values, so it is significance

At alpha = 0.01, the critical value is z0.005 = +/- 2.58

As z = 2.2 lies between the critical values (-2.58 < 2.2 < 2.58) so it is not significance.

Option - B is the correct answer.