0117 This Question: 6 pts in their Support Unsure Males153 Females228 Total 381

Question

0117 This Question: 6 pts in their Support Unsure Males153 Females228 Total 381 488 621 Round to the nearest thousandth as needed.) (b) Find the probability that the person supports the change or is male P(supports the change or is male)- (Round to the nearest thousandth as needed) (c) Find the probability that the person is not unsure or is temale P(is not unsure or is female) Round to the nearest thousandth as needed ) (d) Are the events being male" and "support mutually exclusive? Explain. O B. No, because there are 153 males that support the change Type here to search ?

Explanation / Answer

(a).

P(A+B) = P(A) + P(B) - P(A and B)

P(oppose the change) = 621/1046

P(is female) = 558/1046

P(oppose the change and is female) = (558/1046)*(298/558)

so P(oppose the change or is female) = 621/1046 + 558/1046 - 298/1046

= 881/1046 = 0.8423

(b) P(Supports the change or is male)

P(supports tha change) = 381/1046

P(is male) = 488/1046

P(supports the change and is male) = (488/1046)*(153/488)

so

P(supports the change or is male) = 381/1046 + 488/1046 - 153/1046

= 716/1024 = 0.6845

(c).

P(is not unsure or is female) = P(is not unsure) + P (is female) - P(is not unsure and female)

= 1002/1046 + 558/1046 - ((558/1046)*(526/558))

= 1034/1046

= 0.9885

(d) Mutually exclusive:- two events are mutually exclusive or disjoint if they cannot both be occur simultaneously.

so B option is correct. Because there are 153 men that support the change.

Support oppose unsure total male 153 323 12 488 female 228 298 32 558 total 381 621 44 1046

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